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6x^2-67x-60=0
a = 6; b = -67; c = -60;
Δ = b2-4ac
Δ = -672-4·6·(-60)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5929}=77$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-77}{2*6}=\frac{-10}{12} =-5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+77}{2*6}=\frac{144}{12} =12 $
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